Practicing Success
Practicing Success
CUET Preparation Today
$f(x)=\frac{\sin^3x}{[\frac{x}{π}]+\frac{1}{2}}$, where [·] denotes the greatest integer function is (if x is not integral multiple of π) |
odd function even function neither odd nor even both odd and even |
even function |
$f(-x)=\frac{\sin^3x}{[\frac{x}{π}]+\frac{1}{2}}=\frac{-\sin^3x}{-1-[\frac{x}{π}]+\frac{1}{2}}=\frac{\sin^3x}{\frac{1}{2}+[\frac{x}{π}]}=f(x)$ |
