The HCF and LCM of two numbers are 16 and 96 respectively and the two numbers are in ratio 2 : 3. Find the small number?
Answer & explanation
Correct answer: option 1
LCM = HCF × (product of two other factors)
Ratio of numbers is =2 : 3 (other factors)
ATQ,
96 = 16 × (2R × 3R)
6 = 2R × 3R
R2 = 1 ⇒ R = 1
Hence, Smallest number = 16 × 2R = 32R = 32