The value of $\int\limits^{\frac{\pi}{2}}_{-\frac{\pi}{2}}(x^5+x^3+x+2)dx$ is :
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $2\pi $
$I=\int\limits^{\frac{\pi}{2}}_{-\frac{\pi}{2}}(x^5+x^3+x+2)dx$
$⇒I=\int\limits^{\frac{\pi}{2}}_{-\frac{\pi}{2}}2dx=2(\pi)$
$=2\pi $