In a potentiometer arrangement, a cell of emf 1.5 V gives a balance point at 45.0 cm length of the wire. If the cell is replaced by another cell of emf 2.25 V. Where will the balance point shift to?

63.0 cm 67.5 cm 100.0 cm 90.0 cm

67.5 cm

$ E_1 = \frac{V_0}{L} l_1$ $E_2 = \frac{V_0}{L} l_2$ $\frac{E_1}{E_2} = \frac{l_1}{l_2} = \frac{1.5}{2.25} = \frac{2}{3}$ $l_2 = \frac{3l_1}{2} = 67.5cm$