If \(\frac{a}{6}\) = \(\frac{b}{8}\) = \(\frac{c}{2}\)

then find (\(\frac{a + b + c}{b + c }\)).

\(\frac{8}{5}\)

Given, \(\frac{a}{6}\) = \(\frac{b}{8}\) = \(\frac{c}{2}\)

Here we can directly conclude that 

a = 6, b = 8, c = 2, hence

⇒ (\(\frac{a + b + c}{b + c }\)) = (\(\frac{6 + 8 + 2 }{ 8 + 2 }\)) = \(\frac{16}{10}\) = \(\frac{8}{5}\)