Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electromagnetic Waves

Question:

Assume that a lamp radiates power P uniformly in all directions. What is the magnitude of electric field strength at a distance r from the lamp?

Options:

$\frac{P}{\pi cε_0r^2}$

$\frac{P}{2\pi cεr^2}$

$\sqrt{\frac{P}{2\pi ε_0r^2c}}$

$\sqrt{\frac{P}{\pi ε_0cr^2}}$

Correct Answer:

$\sqrt{\frac{P}{2\pi ε_0r^2c}}$

Explanation:

Intensity $ I = \frac{pressure}{area}=\frac{p}{4\pi r^2}$

=average energy density × velocity

$=\frac{1}{2}ε_0E^2_0c$

$∴ E_0 = \sqrt{\frac{P}{4\pi ε_0r^2c}}=\sqrt{\frac{P}{2\pi ε_0r^2c}}$