A, B and C are three points on a circle such that the angles subtended by the chord AB and AC at the centre O are 110° and 130°, respectively. Then the value of ∠BAC is:

60°

From the following figure,

\(\angle\)AOB = \({110}^\circ\) and \(\angle\)AOC = \({130}^\circ\) 

As we know,

\(\angle\)AOB + \(\angle\)AOC + \(\angle\)BOC = \({360}^\circ\)

\(\angle\)BOC = \({360}^\circ\) - \({110}^\circ\) - \({130}^\circ\) = \({120}^\circ\)

 \(\angle\)BAC = \(\angle\)BOC/2

Therefore, \(\angle\)BAC = \(\frac{120}{2}\) = \({60}^\circ\).