A particle of charge q and mass m moves in a circular orbit of radius r with angular speed w. The ratio of the magnitude of its magnetic moment (m) to that of its angular momentum (L) depends on

m and q only

The correct answer is Option (2) → m and q only

Magnetic moment of a moving charge:

$\mu = \frac{q \cdot \omega \cdot r^2}{2}$

Angular momentum of the particle:

$L = m \cdot \omega \cdot r^2$

Ratio:

$\frac{\mu}{L} = \frac{\frac{q \cdot \omega \cdot r^2}{2}}{m \cdot \omega \cdot r^2}$

$\frac{\mu}{L} = \frac{q}{2m}$

Thus, the ratio depends only on charge and mass.