A particle of charge q and mass m moves in a circular orbit of radius r with angular speed w. The ratio of the magnitude of its magnetic moment (m) to that of its angular momentum (L) depends on
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → m and q only
Magnetic moment of a moving charge:
$\mu = \frac{q \cdot \omega \cdot r^2}{2}$
Angular momentum of the particle:
$L = m \cdot \omega \cdot r^2$
Ratio:
$\frac{\mu}{L} = \frac{\frac{q \cdot \omega \cdot r^2}{2}}{m \cdot \omega \cdot r^2}$
$\frac{\mu}{L} = \frac{q}{2m}$
Thus, the ratio depends only on charge and mass.