Practicing Success
The points (0, -1, -1), (-4, 4, 4), (4, 5, 1) and (3, 9, 4) are |
collinear coplanar forming a square none of these |
coplanar |
Equation of the plane passing through the points (0, -1, -1), (-4, 4, 4) and (4, 5, 1) is $\left|\begin{array}{ccc}x & (y+1) & (z+1) \\ -4 & 5 & 5 \\ 4 & 6 & 2\end{array}\right|=0$ …. (1) The point (3, 9, 4) satisfies the equation (1). Hence (2) is the correct answer. |