If $A=\left[\begin{array}{rr}2 & 3 \\ 5 & -2\end{array}\right]$ then :
Answer & explanation
Correct answer: option 2
$A=\left[\begin{array}{cc}2 & 3 \\ 5 & -2\end{array}\right]$
finding cofactors of A
C11 = -2
C12 = -5
C21 = -3
C22 = 2
so Adj A = $\left[\begin{array}{ll}C_{11} & C_{12} \\ C_{21} & C_{22}\end{array}\right]^{T}=\left[\begin{array}{cc}-2 & -5 \\ -3 & 2\end{array}\right]^{T}=\left[\begin{array}{cc}-2 & -3 \\ -5 & 2\end{array}\right]$ = Adj A
|A| = 2(-2) - 5(3)
= -4 - 15
= -19
so $A^{-1}=\frac{1}{|A|} adj~A=\frac{-1}{19}\left[\begin{array}{ll}-2 & -3 \\ -5 & 2\end{array}\right]$
$\Rightarrow \frac{1}{19}\left[\begin{array}{rr}2 & 3\\ 5 & -2\end{array}\right]$