Phone calls arrive at the rate of 48 per hour at the reservation desk for Indian Airlines. Compute the probability of receiving exactly 10 calls in 15 minutes. |
0.0952 0.1048 0.0763 0.1125 |
0.1048 |
The correct answer is Option (2) → 0.1048 Given number of phone calls arrives per hour is 48. Let random variable X be the number of phone calls in 15 minutes interval of time, then $λ = 48 ×\frac{15}{60}⇒λ = 12$. So, $P(X=10)=\frac{12^{10}e^{-12}}{10}=0.1048$ |