Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Current Electricity

Question:

The sensitivity of a galvanometer of resistance 8722 Wis decreased by 90 times. The shunt used is 

Options:

$ 88\Omega$

$94 \Omega$

$ 90 \Omega$

$98 \Omega$

Correct Answer:

$98 \Omega$

Explanation:

$ \text{Current sensitivity} = \frac{i}{i_g} = 90$

$ Shunt = \frac{Gi_g}{i-i_g} = 98\Omega$