The sensitivity of a galvanometer of resistance 8722 Wis decreased by 90 times. The shunt used is
Answer & explanation
Correct answer: option 4
$ \text{Current sensitivity} = \frac{i}{i_g} = 90$
$ Shunt = \frac{Gi_g}{i-i_g} = 98\Omega$
The sensitivity of a galvanometer of resistance 8722 Wis decreased by 90 times. The shunt used is
Correct answer: option 4
$ \text{Current sensitivity} = \frac{i}{i_g} = 90$
$ Shunt = \frac{Gi_g}{i-i_g} = 98\Omega$