1000 solid spherical balls each of radius 0.6 cm are melted and recast into a single spherical ball. What is the surface area (in cm²) of ball so formed?

144π

We know that,

Volume of sphere = \(\frac{4}{3}\) πr³

Surface area of sphere = 4πr²

We have,

Radius of each ball = 0.6 cm = r

Volume of 1000 smaller ball = 1000 × \(\frac{4}{3}\) × π × (0.6)³

Let radius of bigger ball = R

Now,  \(\frac{4}{3}\) × π × R³ =  1000 × \(\frac{4}{3}\) × π × (0.6)3

= R³ = 1000 × (0.6)³

= R = 10 × 0.6 = 6 cm

Now, Total surface area of bigger ball = 4 × π × (6)² = 144π cm²