Linear inequalities corresponding to the shaded feasible region OABCO in the given figure are

$4x + 3y ≤ 12, 3x+4y ≤ 12, x≥0,y≥0$

The correct answer is Option (1) → $4x + 3y ≤ 12, 3x+4y ≤ 12, x≥0,y≥0$

From the figure:

Axes give: $x\ge 0,\; y\ge 0$

Line CE through (0,3) and (4,0): $3x+4y\le 12$

Line DA through (0,4) and (3,0): $4x+3y\le 12$

The feasible region OABCO is given by:

$x\ge 0,\; y\ge 0,\; 3x+4y\le 12,\; 4x+3y\le 12$