With respect to the following shaded feasible region (ABCDEFA), the maximum value of the objective function $z=3x+4y-2$ is at point(s): |
Point B and D Point F only Point A and C Point E only |
Point E only |
The correct answer is Option (4) → Point E only Objective function: $z = 3x + 4y - 2$ At $E(2,5)$: $z = 3*2 + 4*5 - 2 = 6 + 20 - 2 = 24$ Answer: $z = 24$, which gives the maximum value. |