
Answer & explanation
Correct answer: option 4
$\text{Input A and B will pass through AND gate so their output is A.B , Input C will pass through NOT gate so its OUTPUT is }\bar C.$
$\text{Now both A.B and }\bar C \text{ will pass through NAND GATE so the final output is} \bar({AB}.\bar{C}) = \bar{AB}+ C$
$\Rightarrow \text{If A = 1 , B = 1 , C= 0 then output is zero.}$