Practicing Success
a b c d |
d |
$\text{Input A and B will pass through AND gate so their output is A.B , Input C will pass through NOT gate so its OUTPUT is }\bar C.$ $\text{Now both A.B and }\bar C \text{ will pass through NAND GATE so the final output is} \bar({AB}.\bar{C}) = \bar{AB}+ C$ $\Rightarrow \text{If A = 1 , B = 1 , C= 0 then output is zero.}$ |