The sides of a triangle are 24 cm, 26 cm and 10 cm.At each of its vertex, circles of radius 4.2 cm are drawn. What is the area (in $cm^2$) of the portion covered by the three sectors of the circle ? $(\pi = \frac{22}{7})$

27.72

We have a concept,

The area made by three circles in three vertices of a triangle of the same radius will be half the area of the circle.

We have,

The sides of the triangle = 24 cm, 26 cm, and 10 cm.

Area of the triangle = \(\frac{1}{2}\) × 24 × 10 = 120 cm²

The radius of the circle = 4.2 cm

The total angle created in three circles in the vertices = 180° 

The area of the triangle which is inside the common portion of the triangle and circle = (1/2) π (4.2)² = 27.72 cm²