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If $sin^{-1}(\frac{x}{5})+cosec^{-1}(\frac{5}{4})=\frac{\pi}{2},$ then the value of x is : |
1 3 4 5 |
3 |
The correct answer is Option (2) → 3 $cosec^{-1}(\frac{5}{4})+\sin^{-1}(\frac{x}{5})=\frac{\pi}{2}$ $\sin^{-1}(\frac{x}{5})=\sec^{-1}\frac{5}{4}$ $\sin^{-1}(\frac{x}{5})=\cos^{-1}\frac{4}{5}$ so $x=3$ as $3^2+4^2=5^2$ |
