Target Exam

CUET

Subject

Physics

Chapter

Electric Charges and Fields

Question:

Three charges q, -q, q placed at the vertices of an equilateral triangle as shown in figure. What is the magnitude of force on charge placed at position 3 due to the presence of other two charges?

Options:

$\frac{1}{2 \pi \varepsilon_{o}} \frac{q^2}{l}$

$\frac{\sqrt{3}}{4 \pi \varepsilon_{o}} \frac{q^2}{l^2}$

$\frac{\sqrt{5}}{8 \pi \varepsilon_{o}} \frac{q}{\sqrt{l}}$

$\frac{1}{4 \pi \varepsilon_{o}} \frac{q^2}{\sqrt{l}}$

Correct Answer:

$\frac{\sqrt{3}}{4 \pi \varepsilon_{o}} \frac{q^2}{l^2}$

Explanation:

The correct answer is Option (2) → $\frac{\sqrt{3}}{4 \pi \varepsilon_{o}} \frac{q^2}{l^2}$

According to Coloumb's law,

$F=K\frac{|q_1q_2|}{r^2}$

$F_{13}=K\frac{q^2}{l^2},F_{23}=K\frac{q^2}{l^2}$

$F_{net}=\sqrt{(F_{13x}+F_{23x})^2+(F_{13y}+F_{23y})^2}$

$=2F_{13x}=2F_{13}\cos(30°)$

$=K\frac{q^2}{l^2}\sqrt{3}$