Target Exam

CUET

Subject

Chemistry

Chapter

Physical: Solutions

Question:

Match List-I with List-II

List-I Solute

List-II van't Hoff factor, $i$

(A) Benzoic acid in benzene

(I) 3

(B) $K_2SO_4$ (aq)

(II) 2

(C) Urea (aq)

(III) 0.5

(D) KOH (aq)

(IV) 1

Choose the correct answer from the options given below:

Options:

(A)-(I), (B)-(II), (C)-(III), (D)-(IV)

(A)-(II), (B)-(I), (C)-(III), (D)-(IV)

(A)-(I), (B)-(II), (C)-(IV), (D)-(III)

(A)-(III), (B)-(I), (C)-(IV), (D)-(II)

Correct Answer:

(A)-(III), (B)-(I), (C)-(IV), (D)-(II)

Explanation:

The correct answer is Option (4) → (A)-(III), (B)-(I), (C)-(IV), (D)-(II)

List-I Solute

List-II van't Hoff factor, $i$

(A) Benzoic acid in benzene

(III) 0.5

(B) $K_2SO_4$ (aq)

(I) 3

(C) Urea (aq)

(IV) 1

(D) KOH (aq)

(II) 2

(A) Benzoic acid in benzene — (III) 0.5

Benzoic acid undergoes dimerization in non-polar solvents like benzene due to hydrogen bonding. Two molecules join to form one single unit (a dimer).

  • Since the number of particles is halved, $i = 0.5$.

(B) $K_2SO_4$ (aq) — (I) 3

Potassium sulfate is a strong electrolyte. In an aqueous solution, it dissociates completely into three ions:

$K_2SO_4 \rightarrow 2K^+ + SO_4^{2-}$

  • Total particles = 3, so $i = 3$.

(C) Urea (aq) — (IV) 1

Urea ($NH_2CONH_2$) is a non-electrolyte. It dissolves in water as whole molecules and does not undergo dissociation or association.

  • Total particles = 1, so $i = 1$.

(D) KOH (aq) — (II) 2

Potassium hydroxide is a strong base and dissociates completely into two ions:

$KOH \rightarrow K^+ + OH^-$

  • Total particles = 2, so $i = 2$.