Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Units and Measurements

Question:

Match the Column - I with Column - II.

Column – I

Column - II

A. Capacitance

(p) volt (ampere)–1

B. Magnetic induction

(q) volt-sec (ampere)–1

C. Inductance

(r) newton(ampere)–1 (metre)–1

D. Resistance

(s) coulomb2 (joule)–1

Options:

A → s ; B→ r ; C→ q ; D→ p

A → r ; B→ p ; C→ s ; D→ q

A → s ; B→ q ; C→ r ; D→ p

A → q ; B→ r ; C→ s ; D→ p

Correct Answer:

A → s ; B→ r ; C→ q ; D→ p

Explanation:

The correct answer is Option (1) → A → s ; B→ r ; C→ q ; D→ p

(A) Energy, $E=\frac{Q^2}{2C}$
$∴ \text{Capacitance, }C = Q^2/2E$ = (Joule)–1 coulomb2

(B) Force, F = Bil
$∴\text{ Magnetic Induction, }B=\frac{F}{il}$ = newton (ampere)–1 (metre)–1

(C) Induced emf, $e = L Δi/Δt$
$∴\text{ Inductance, }L=\frac{e Δt}{Δi}$ = volt– sec (ampere)–1

(D) Resistance, $R=\frac{V}{I}$ = volt (ampere)–1