Z is increased successively by $11\frac{1}{9}$% and 10% to get R. If R = 165, then what is the value of Z?
Answer & explanation
Correct answer: option 4
11\(\frac{1}{9}\)% = \(\frac{1}{9}\) & 10% = \(\frac{1}{10}\)
Let Z = 9R
ATQ ,
Increased value of Z = 9R + 9R × \(\frac{1}{9}\) = 9R + 1R = 10R
Now again Increased by 10% ,
Increased Number = 10R + 10% of 10R = 11R
ATQ,
11R = 165
1R = 15
Value of Z = 9R
= 9 × 15
= 135
So , Value of Z is 135.