Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Matrices

Question:

Let M and N be two 3 × 3 non-singular skew-symmetric matrices such that $MN = NM$. If $P^T$ denotes the transpose of P, then $M^2 N^2 (M^T N)^{-1} (MN^{-1})^T$ is equal to

Options:

$M^2$

$-N^2$

$-M^2$

$MN$

Correct Answer:

$-M^2$

Explanation:

We know

$M^T=-M$

$N^T=-N$

$MN = NM$

So $M^{-1}N^{-1}=N^{-1}M^{-1}$

$M^2 N^2 (M^TN)^{-1} (MN^{-1})^T$

$=M^2 N^2 (N^{-1} ×(M^T)^{-1})×((N^{-1})^T M^T)$

$=-M^2N^2N^{-1}M^{-1}N^{-1}M$

$=-M^2$