The population of village has been continuously increasing at the rate of 10% per year. If its present population is 54,450, what was it two years ago?

48000 45000 52000 50000

45000

Let initial population = 100x 100x × \(\frac{110}{100}\) × \(\frac{110}{100}\) = 54450 100x × \(\frac{11}{10}\) × \(\frac{11}{10}\) = 54450 100x = 45000 So , initial population = 45000