The population of village has been continuously increasing at the rate of 10% per year. If its present population is 54,450, what was it two years ago?
Answer & explanation
Correct answer: option 2
Let initial population = 100x
100x × \(\frac{110}{100}\) × \(\frac{110}{100}\) = 54450
100x × \(\frac{11}{10}\) × \(\frac{11}{10}\) = 54450
100x = 45000
So , initial population = 45000