Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If x + y + z = 8, and $x^2 + y^2 + z^2 = 20$ then the value of $x^3 + y^3 + z^3 − 3xyz$ is _______.

Options:

16

10

15

-16

Correct Answer:

-16

Explanation:

If x + y + z = 8, and $x^2 + y^2 + z^2 = 20$

Find the value of $x^3 + y^3 + z^3 − 3xyz$

If the number of equations are less than the number of variables then we can put the extra variables according to our choice = 

So here two equations given and three variables are present so put z = 0

x + y = 8, and $x^2 + y^2  = 20$

Find the value of $x^3 + y^3$= ?

( a + b )2 = a2 + b2 + 2ab

( 8)2 = 20 + 2xy

64 =  20 + 2ab

2xy = 44

xy = 22

$x^3 + y^3$ = 83 - 3 × 8 × 22

$x^3 + y^3$ = 512 - 528

$x^3 + y^3$ = -16