In triangle ABC. AD is the internal bisector of ∠A meeting BC at D. If BD = 3.6 cm and BC = 8 cm, then the ratio of AB to AC will be:

9 : 11

We know that,

In ΔABC, if AD is the internal bisector of ∠A meeting BC at D, then AB/AC = BD/DC AD is the internal bisector of ∠A meeting BC at D

We have,

BD = 3.6 cm and BC = 8 cm

According to the question,

DC = BC – BD

= DC = 8 – 3.6 = 4.4

So, AB/AC = BD/DC

= AB/AC = 3.6/4.4

= AB : AC = 3.6 : 4.4

= AB : AC = 9 : 11