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Interference fringes from sodium light (λ = 5890 Å) in a double slit experiment have an angular width 0.20°, To increase the fringe width by 10%, new wavelength should be |
5896 Å 7321 Å 6300 Å 6479 Å |
6479 Å |
$θ_1=\frac{λ_1}{d},\,θ_2=\frac{λ_2}{d}$ $∴\frac{θ_1}{θ_2}=\frac{λ_1}{λ_2}$ $∴λ_2=λ_1×\frac{θ_2}{θ_1}$ or $λ_2=5890×\frac{0.22}{0.20}=6479Å$ |
