If $cos^{-1}\alpha + cos^{-1}\beta +cos^{-1}\gamma = 3\pi $ then value of $\alpha^2\beta^2\gamma^2 +3 (\alpha + \beta + \gamma )= $
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → -8
$\cos^{-1}\alpha + \cos^{-1}\beta +\cos^{-1}\gamma = 3\pi $
$⇒α=-1=β=γ$
so $\alpha^2\beta^2\gamma^2 +3 (\alpha + \beta + \gamma)$
$=1-9=-8$