Practicing Success
Practicing Success
CUET Preparation Today
If $cos^{-1}\alpha + cos^{-1}\beta +cos^{-1}\gamma = 3\pi $ then value of $\alpha^2\beta^2\gamma^2 +3 (\alpha + \beta + \gamma )= $ |
-8 0 10 -10 |
-8 |
The correct answer is Option (1) → -8 $\cos^{-1}\alpha + \cos^{-1}\beta +\cos^{-1}\gamma = 3\pi $ $⇒α=-1=β=γ$ so $\alpha^2\beta^2\gamma^2 +3 (\alpha + \beta + \gamma)$ $=1-9=-8$ |
