The sum of present ages of A and B is 48 years. Today B is 4 years older than C. The respective ratio of the present ages of A and C is 4 : 7. What was B's age two years ago?
Answer & explanation
Correct answer: option 2
A + B = 48 years
ATQ,
⇒ B = C + 4
⇒ A + C + 4 = 48
⇒ A + C = 44 and
A : C
4 : 7 → 11R = 44 ⇒ 1R = \(\frac{44}{11}\) = 4
×4 ×4
16 28 (present age)
⇒ Hence, B's present age = 28 + 4 = 32
⇒ Age of B two years ago = 32 - 2 = 30 years