The sum of present ages of A and B is 48 years. Today B is 4 years older than C. The respective ratio of the present ages of A and C is 4 : 7. What was B's age two years ago? |
32 30 28 34 |
30 |
A + B = 48 years ATQ, ⇒ B = C + 4 ⇒ A + C + 4 = 48 ⇒ A + C = 44 and A : C 4 : 7 → 11R = 44 ⇒ 1R = \(\frac{44}{11}\) = 4 ×4 ×4 16 28 (present age) ⇒ Hence, B's present age = 28 + 4 = 32 ⇒ Age of B two years ago = 32 - 2 = 30 years |