In a constituency, 55% of the total number of voters are males and the rest are females. If 40% of the males are illiterate and 40% of the females are literate, then by what percentage is the number of illiterate females more than that of the illiterate males (correct to one decimal place)?
Answer & explanation
Correct answer: option 1
40% = \(\frac{2}{5}\) & 60% = \(\frac{3}{5}\)
Let total population = 100
Number of males = 55 & Number of females = 45
Number of illiterate male = \(\frac{2}{5}\) × 55 = 22
Number of illiterate females = \(\frac{3}{5}\) × 45 = 27
Required percentage = \(\frac{27 - 22}{22}\) × 100
= \(\frac{5}{22}\) × 100
= 22.7%