30 people went to a restaurant for a dinner party. 20 of them paid ₹880 each and each of the rest of them paid ₹110 more than the average of the total expenses. What was the total expense (in ₹) for the dinner?

28,050

Let average bill = X

Total bill = 20 × 880 + 10(X + 110)

= 17600 + 10X + 1100 = 18700 + 10X

ATQ ,

X = \(\frac{18700 + 10X }{30}\)

30X = 18700 + 10X

20X = 18700

X = 935

Total bill = 30X = 30 × 935 = 28050