The area of the region bounded by the line $y = 2x$ and the x-axis between $x = -2$ and $x = 2$ is

8 sq.units

The correct answer is Option (1) → 8 sq.units

Given: $y = 2x$

Required area between $x = -2$ and $x = 2$:

$A = \int_{-2}^{2} |2x|\,dx = 2\int_{0}^{2} 2x\,dx = 4\left[\frac{x^{2}}{2}\right]_{0}^{2}$

$A = 4\left(\frac{4}{2}\right) = 4 \times 2 = 8$

Area = 8 sq. units