If cos A = 2 sin A, then cosec A is equal to :

$\frac{1}{2}$ $\frac{1}{\sqrt{5}}$ 2 $\sqrt{5}$

$\sqrt{5}$

Given :- cosA = 2 sinA ⇒ cotA = \(\frac{2 }{1}\)         [ cotA = \(\frac{B}{P}\) ] P² + B² = H² 1² + 2² = H² H = √5 Now, cosec A = \(\frac{H}{P}\) = \(\frac{√5}{1}\) = √5