CUET Preparation Today
The solution X of the matrix equation AX = B, where A is an invertible matrix, is given by |
$X=BA^{-1}$ $X=A^{-1} B$ $X=A^{-1} B^{-1}$ $X=A B^{-1}$ |
$X=A^{-1} B$ |
The correct answer is Option (2) → $X=A^{-1} B$ $AX = B$ so pre multiplication with $A^{-1}$ $A^{-1}AX = A^{-1}B$ $⇒X=A^{-1}B$ |
