$∫\frac{1}{(x+1)(x+2)}dx=$

$log(x+1)(x=2)+C;$ Where C is arbitrary constant of integration $log\frac{x+1}{x+2}+C;$ Where C is arbitrary constant of integration $log\frac{x+2}{x+1}+C;$Where C is arbitrary constant of integration $-log(x+1)(x=2)+C;$ Where C is arbitrary constant of integration

$log\frac{x+1}{x+2}+C;$ Where C is arbitrary constant of integration