Alloy A contains copper and zinc in the ratio of 4 : 3 and alloy B contains zinc and copper in the ratio of 2 : 5. A and B are taken in the ratio of 5 : 6 and melted to form a new alloy. The percntage of zinc in the new alloy is closed to?
Answer & explanation
Correct answer: option 4
Alloy (A) = 4 : 3 (Given)
Alloy (B) = 2 : 5 (Given)
When A and B are taken in the ratio of 5 : 6 then,
New alloy =
A = (4 + 3) = 7 × (5) = 35
⇒ Zinc in new alloy A = 35 × \(\frac{3}{7}\) = 15
B = (2 + 5) = 7 × (6) = 42
⇒ Zinc in new alloy B = 42 × \(\frac{2}{7}\) = 12
Total zinc in new alloy = 15 + 12 = 27
Zinc% in new alloy = \(\frac{27}{35 + 42}\) × 100
= 35.06%