Alloy A contains copper and zinc in the ratio of 4 : 3 and alloy B contains zinc and copper in the ratio of 2 : 5. A and B are taken in the ratio of 5 : 6 and melted to form a new alloy. The percntage of zinc in the new alloy is closed to?

35.06%

Alloy (A) = 4 : 3 (Given)

Alloy (B) = 2 : 5 (Given)

When A and B are taken in the ratio of 5 : 6 then,

New alloy =

A = (4 + 3) = 7 × (5) = 35 

⇒ Zinc in new alloy A = 35 × \(\frac{3}{7}\) = 15

B = (2 + 5) = 7 × (6) = 42

⇒ Zinc in new alloy B = 42 × \(\frac{2}{7}\) = 12

Total zinc in new alloy = 15 + 12 = 27

Zinc% in new alloy = \(\frac{27}{35 + 42}\) × 100

                              = 35.06%