A charged particle with charge $q$ and mass ' $m$ ' is moving with velocity $160 \mathrm{~ms}^{-1}$ in the region of magnetic field $\mathrm{B}$ at an angle $60^{\circ}$ with the direction of $\overrightarrow{\mathrm{B}}$. The pitch of helix formed by particle will be:

\(\frac{160 \pi m}{q B} \)

$ T = \frac{2\pi m }{qB}$

$Pitch(P) =\frac{2\pi mvcos\theta}{qB} = \frac{2\pi m\times 160 cos 60^0}{qB} = \frac{160\pi m}{qB}$