Find the value of (cos^225° + cos^265°)/(sin^290°) - tan245° + cot230°

Formula → [cos²A + cos²B = 1, when A + B = 90°]

Here, (25° + 65° = 90°), therefore,

⇒ \(\frac{cos^225°\;+\;cos^265°}{sin^290°}\) - tan²45° + cot²30°

= \(\frac{1}{1}\) - 1 + (\(\sqrt {3}\))²

= 1 - 1 + 3 = 3