A die is thrown 6 times. If getting an odd number is a success, then the probability of at least 5 successes is

$\frac{7}{64}$

The correct answer is Option (3) → $\frac{7}{64}$ **

$P(\text{odd})=\frac{3}{6}=\frac{1}{2}$

$X\sim \text{Binomial}(6,\frac{1}{2})$

$P(X\ge 5)=P(X=5)+P(X=6)$

$=\frac{\;6+1\;}{64}$

The required probability is $\frac{7}{64}$.