Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Dual Nature of Radiation and Matter

Question:

An electron (mass m) with an initial velocity $v=v_0\hat i(v_0>0)$ is in an electric field $E=-E_0\hat i$ ($E_0$ = constant > 0). Its de-Broglie wavelength at time t is given by:

Options:

$\frac{λ_0}{(1+\frac{eE_0}{m}\frac{t}{v_0})}$

$λ_0(1+\frac{eE_0t}{mV_0})$

$λ_0$

$λ_0t$

Correct Answer:

$\frac{λ_0}{(1+\frac{eE_0}{m}\frac{t}{v_0})}$

Explanation:

Initial de-Broglie wavelength of electron, $λ_0=\frac{h}{mv_0}$   (i)

Force on electron in electric field, $F=-eE=-e[-E_0\hat i]=eE_0\hat i$

Acceleration of electron, $a=\frac{F}{m}=\frac{eE_0\hat i}{m}$

Velocity of electron after time t, $v=v_0\hat i+(\frac{eE_0\hat i}{m})t=(v_0+\frac{eE_0}{m}t)\hat i=v_0(1+\frac{eE_0}{m}t)\hat i$

de-Broglie wavelength associated with electron at time t is $λ=\frac{h}{mv}$

$⇒=\frac{h}{m[v_0(1+\frac{eE_0}{m}t)]}=\frac{λ_0}{[1+\frac{eE_0}{m}t]}$  $[∵λ_0=\frac{h}{mv_0}]$