Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Wave Optics

Question:

Case based

The British physicist Thomas used an ingenious technique to lock the phases of the waves emanating from two coherent sources $S_1$ and $S_2$. As these sources were derived from same source symmetrically placed wrt $S_1$ and $S_2$, the phases of waves were same. If any abrupt change happens in original sources, will manifest exactly similar phase changes in the light coming out of two sources $S_1$ to $S_2$. Due to constructive interference and destructive interference at different points in space and screen alternate dark and bright fringes of equal width were obtained. This pattern was called as interference pattern. The width of each band was equal with central fringe as bright fringe.

The phase difference $(\Delta \phi)$ between two super imposing waves to obtain constructive interference and hence bright band, is:

Options:

$\Delta \phi=np ; ~n=1,2,3,4,5$

$\Delta \phi=2 n p ; ~n=0,2,3,4,5$

$\Delta \phi=\frac{n \pi}{2} ~~n=1,2,3,4,5$

$\Delta \phi=\frac{3 n \pi}{2} ~~n=1,2,3,4,5$

Correct Answer:

$\Delta \phi=np ; ~n=1,2,3,4,5$

Explanation:

The correct answer is Option (1) → $\Delta \phi=np ; ~n=1,2,3,4,5$