Practicing Success
If $a + b + c = 2, \frac{1}{a}+\frac{1}{b}+\frac{1}{c}, ac =\frac{4}{b}$ and $a^3 + b^3 +c^3 = 28$, find the value of $a^2 + b^2 + c^2$. |
6 12 10 8 |
8 |
If $a + b + c = 2, \frac{1}{a}+\frac{1}{b}+\frac{1}{c}=0, ac =\frac{4}{b}$ and $a^3 + b^3 +c^3 = 28$, find the value of $a^2 + b^2 + c^2$ = ? We know that, a3 + b3 + c3 - 3abc = ( a + b + c ) ( a2 + b2 + c2 - (ab + bc + ca)) $\frac{1}{a}+\frac{1}{b}+\frac{1}{c}$ =0 \(\frac{bc + ac + ab}{abc}\) = 0 = bc + ac + ab = 0 Given,$ac =\frac{4}{b}$ then, abc = 4 Put these values in the given formula,. 28 - 3 × 4 = 2 × (a2 + b2 + c2 - 0) = \(\frac{(28 - 12)}{2}\) = a2 + b2 + c2 = a2 + b2 + c2 = \(\frac{(16)}{2}\) = a2 + b2 + c2 = 8 |