In ΔXYZ, I is the incentre of the ΔXYZ. If ∠XYZ = 40 degree, then what is the value of ∠XIZ ?
Answer & explanation
Correct answer: option 2
In \(\Delta \)XYZ, I is the incentre
\(\angle\)XIZ = 90 + (\(\frac{1}{2}\) x \(\angle\)XYZ)
= \(\angle\)XIZ = 90 + (\(\frac{1}{2}\) x 40)
= \(\angle\)XIZ = 90 + 20
= \(\angle\)XIZ = 110
Therefore, \(\angle\)XIZ is \({110}^\circ\).