For a certain period, simple interest on ₹1000 at 10% per annum is ₹100 more than that on ₹800. Find the period (in years).

5

simple interest (S) on Principal (P) ₹1000 at Rate (R)10% per annum is ₹100 more than that on ₹800

P1 = 1000

R = 10% p.a.

T = T

S1 = 1000*10*T/100

P2 = 800

R = 10% p.a.

S2 = 800*10*T/100

Given, S1 = S2 + 100

1000*10*T/100 = 800*10*T/100 + 100

10000T = 8000T+10000

2000T = 10000

T = 5 years

The correct answer is Option (3) → 5