A person has to cover a distance of 60 km. If he increases his speed by 3 km/hr he reaches 1 hr early. Find his initial speed (in km/hr).
Answer & explanation
Correct answer: option 3
Let the initial speed = x km/hr
ATQ,
\(\frac{60}{x}-\frac{60}{x+3}=1\)
let x = 12 (by using option)
\(\frac{60}{12}-\frac{60 }{150}=1\)
5 – 4 = 1 (satisfied)