A policeman saw a thief from distance of 450m and started running towards him. If speed of policeman and thief are 23 km/hr and 20 km/hr respectively , the distance covered by thief before he is being caught is:
Answer & explanation
Correct answer: option 4
P T
Ι------------------Ι---------------Ι
450 m
Speed (T) = 20km/h
Speed (P) = 23km/h
Relative speed = (23 - 20) km/h = 3km/h = 3 × \(\frac{5}{18}\) m/sec
Now,
Time = \(\frac{450}{{3} × \frac{5}{18}} \) = 540 sec
Distance (T) = 20 × \(\frac{5}{18}\) × 540 = 3000 m = 3 km