Target Exam

CUET

Subject

Physics

Chapter

Electromagnetic Induction

Question:

In an AC generator, a coil of 20 turns each with area $2×10^{-2} m^2$ is rotated at 50 revolutions per sec in a uniform magnetic field of 2.5 T. The maximum induced emf produced is

Options:

157 V

314 V

220 V

190 V

Correct Answer:

314 V

Explanation:

The correct answer is Option (2) → 314 V

The maximum induced emf in generator is -

$ε_{max}=NABω$

$=(20)(2×10^{-2})(2.5)(2\pi×50)$

$=100\pi V$

$=314 V$