In an AC generator, a coil of 20 turns each with area $2×10^{-2} m^2$ is rotated at 50 revolutions per sec in a uniform magnetic field of 2.5 T. The maximum induced emf produced is
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 314 V
The maximum induced emf in generator is -
$ε_{max}=NABω$
$=(20)(2×10^{-2})(2.5)(2\pi×50)$
$=100\pi V$
$=314 V$