The equation of a straight line on a point (3, -5) and slope 2 is :

2x - y - 11 = 0 3x - 5y - 2= 0 5x - 2y + 3 = 0 3x - 2y - 5 = 0

2x - y - 11 = 0

We know that, (y - y1) = m(x - x1) m = slope of a line, and (x1, y1) We have, The equation of a straight line on a point (3, -5) The slope of a line = 2.  x1 = 3, y1 = -5 According to the formula , = y - (-5) = 2 × (x - 3) = y + 5 = 2x -6 = 2x - y - 11 = 0