A 5 m long ladder is placed against a wall. It is inclined at an angle of 30° to the ground. The distance (in m) of the foot of the ladder from the wall is (Given √3 = 1.732)?

4.33

AC = ladder

Θ = angle of inclination

BC = distance of foot from wall

cos Θ = \(\frac{BC}{AC}\) ⇒ cos 30° = \(\frac{BC}{5}\)

                                        ⇒ \(\frac{\sqrt {3}}{2}\) = \(\frac{BC}{5}\)

                                        ⇒ \(\frac{5 × 1.732}{2}\) = BC

                                    BC = 4.33 m