The side of an equilateral triangle is 4 cm. What is its area?

$6\sqrt{3}cm^2$ $8\sqrt{3}cm^2$ $9\sqrt{3}cm^2$ $4\sqrt{3}cm^2$

$4\sqrt{3}cm^2$

The side of a equilateral triangle = 4 cm. Area of a equilateral triangle = \(\frac{\sqrt {3}}{4}\) × (side)2 Area of a equilateral triangle = \(\frac{\sqrt {3}}{4}\) × (4)2 = \(\frac{\sqrt {3}}{4}\) × 16 = $4\sqrt{3}cm^2$